Manacher Longest Palindromic Substring in Java
Manacher reuses mirrored palindrome radii to find a longest contiguous palindrome in linear time..
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 | // Manacher Longest Palindromic Substring in Java // // PURPOSE // Manacher reuses mirrored palindrome radii to find a longest contiguous palindrome in // linear time. // // METHOD // Compute odd and even center radii in separate passes. Reuse the mirror radius within the // current rightmost palindrome, then expand only beyond its known boundary. // // COMPLEXITY // O(n) time and O(n) auxiliary space. // // CONTRACT // Integer tokens. Returns longest palindrome LENGTH; empty input returns zero. // Public APIs infer array lengths except in C, which accepts pointer/length pairs. Vertex // counts and matrix dimensions remain explicit. Arrays must contain signed 32-bit integers. // Sorted order, correct tree topology, and caller-owned data-structure invariants are // preconditions; checking them on every query would change query complexity. // Scalar and shape checks are included. Value-range checks are included where needed to // prevent invalid indexing or nontermination. Allocation sizes are capped at 4,000,000 // workspace entries. Arithmetic outside Python raises an error on 32-bit overflow; Python // uses arbitrary precision. Native allocation failures propagate. In-place outputs may be // partly updated after arithmetic failure. These are single-threaded, in-memory // implementations. // // LANGUAGE DETAILS // Java 17+: primitive int arrays, Arrays.binarySearch for LIS, and Math exact arithmetic. // Invalid input throws IllegalArgumentException; arithmetic overflow throws // ArithmeticException. // // EXAMPLE // Expected return: 4. // Run: javac AlgorithmExample.java && java AlgorithmExample // Tests for this exact source artifact run before publication. The accompanying source // archive includes unit cases, runtime results, and source hashes. class AlgorithmExample { static void alg_require(boolean valid) { if (!valid) throw new IllegalArgumentException("invalid algorithm input"); } static int alg_size(int n) { alg_require(n>=0 && n<=4000000); return n; } static int manacher(int[] a) { java.util.Objects.requireNonNull(a, "a"); int n = a.length; alg_require(((n >= 0) && (n <= 1000000))); alg_require((a.length == n)); int[] radius = new int[alg_size(Math.addExact(n, 1))]; int parity = 0; int left = 0; int right = Math.negateExact(1); int i = 0; int k = 0; int best = 0; while ((parity < 2)) { left = 0; right = Math.negateExact(1); i = 0; while ((i < n)) { k = Math.subtractExact(1, parity); if ((i <= right)) { k = Math.min(radius[Math.addExact(Math.subtractExact(Math.addExact(left, right), i), parity)], Math.addExact(Math.subtractExact(right, i), 1)); } while (((Math.subtractExact(Math.subtractExact(i, k), parity) >= 0) && (Math.addExact(i, k) < n) && (a[Math.subtractExact(Math.subtractExact(i, k), parity)] == a[Math.addExact(i, k)]))) { k = Math.addExact(k, 1); } radius[i] = k; best = Math.max(best, Math.addExact(Math.subtractExact(Math.multiplyExact(2, k), 1), parity)); if ((Math.subtractExact(Math.addExact(i, k), 1) > right)) { left = Math.addExact(Math.subtractExact(Math.subtractExact(i, k), parity), 1); right = Math.subtractExact(Math.addExact(i, k), 1); } i = Math.addExact(i, 1); } parity = Math.addExact(parity, 1); } return best; } public static void main(String[] args) { int[] a = new int[] {1, 2, 2, 1}; int result = manacher(a); System.out.println(result); } } |